The rate law for the reaction-RCl - NaOH - ROH - NaCl is given by-Rate - k-RCl- The rate of this reaction is IIT-JEE- 1990

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First Order Reaction

The rate law ...

Question

The rate law for the reaction:
$R C l + N a O H \to R O H + N a C l$ is given by;
Rate = $k [R C l]$ . The rate of this reaction is

(IIT-JEE, 1990)

Doubled by doubling the concentration of NaOH

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Halved by reducing the concentration of RCl by one half

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Increases by increasing the temperature of the reaction.

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Unaffected by change of temperature

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Solution

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R C l + N a O H (a q) \to R O H + N a C l

R a t e = k [R C l]

R C l + N a O H (a q) \to R O H + N a C l

R a t e = k [R C l]

The rate law for the reaction:
$R C l + N a O H \to R O H + N a C l$ is given by;
Rate = $k [R C l]$ . The rate of this reaction is

(IIT-JEE, 1990)

R C l + N a O H (a q .) ⟶ R O H + N a C l

= k [R C l]

R C l + N a O H (a q .) \to R O H + N a C l

R a t e = k_{1} [R C l] .

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