wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The solution set for the following inequation is:
x3x2113<16, xϵR


A
{85<x<3,xϵR}
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
{85x<3,xϵR}
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
{85x3,xϵR}
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
{85<x3,xϵR}.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B {85x<3,xϵR}

Given: x3x2113<16

x33x86 and 3x86<16


Rule: If both the sides of an inequation are multiplied or divided by the same positive number, then the sign of the inequality will remain the same.
On multiplying left hand side inequation by 6 and right hand side inequation by 6 in both the inequations, we get;

2x3x8 and 3x8<1

8x3x+2x and 3x<1+8

85x and 3x<9

{85x<3,xϵR}.


flag
Suggest Corrections
thumbs-up
3
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Solving Inequalities
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon