Question

The temperature of gas is increased from $400\text{K}$ to $600\text{K}$ keeping the volume of the gas constant. If initially the gas exerted a pressure of $3\text{kPa}$ on the walls of the container, then the final pressure of the gas is (in $\text{kPa}$)

• A. $6$
• B. $4.5$
• C. $0.045$
• D. $0.06$

Answer 1

The correct option is B $4.5$

Given,
$T_i=400\text{K};T_f=600\text{K};P_i=3\text{kPa}$
At constant volume,
$\frac{P_i}{T_i}=\frac{P_f}{T_f}$
$\Rightarrow P_f=\frac{P_i{T}_f}{T_i}=\frac{3\times 600}{400}=4.5\text{kPa}$