Question

To win an election, a candidate needs ${\frac{3}{4}}^{th}$ of the votes cast. If after ${\frac{2}{3}}^{rd}$ of the votes have been counted, a candidate has ${\frac{5}{6}}^{th}$ of what he needs, then what part of the remaining votes does he still he need?

• A.
• B.
• C.
• D.

Answer 1

The correct option is C

$Letthetotalvotescast=x$

$Votescounted=\frac{2}{3}x$

$Votesuncounted=\frac{1}{3}x$

$Remainingvotesthecandidateneeds=\frac{1}{6}\times \frac{3}{4}x=\frac{1}{8}x$

$\therefore$ $Requiredpart=\frac{\frac{1}{8}x}{\frac{1}{3}x}=\frac{3}{8}$