Twenty litres of $N O$ gas react with excess oxygen. How many litres of ${N O}_{2}$ gas are produced if the $N O$ gas reacts completely?

$2 N O + O_{2} \to 2 {N O}_{2}$

5

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10

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20

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40

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50

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Solution

The correct option is C $20$ L
The balanced chemical equation is $2 N O + O_{2} \to 2 N O_{2}$

Thus, 2 moles of $N O$ will produce 2 moles of $N O_{2}$ .

Also, the volume is directly proportional to the number of moles.

Therefore, 20 L of $N O$ will produce $20 \times \frac{2}{2} = 20$ L of $N O_{2}$ .

Hence, option C is correct.

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Twenty litres of NO gas react with excess oxygen. How many litres of NO2 gas are produced if the NO gas reacts completely? 2NO+O2→2NO2

The correct option is C 20 LThe balanced chemical equation is 2NO+O2→2NO2Thus, 2 moles of NO will produce 2 moles of NO2.Also, the volume is directly proportional to the number of moles.Therefore, 20 L of NO will produce 20×22=20 L of NO2.Hence, option C is correct.

Twenty litres of $N O$ gas react with excess oxygen. How many litres of ${N O}_{2}$ gas are produced if the $N O$ gas reacts completely?

$2 N O + O_{2} \to 2 {N O}_{2}$