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Byju's Answer
Standard XII
Physics
Impedance in RLC Circuit
Two circuits ...
Question
Two circuits are shown in the figure (a) & (b). At a frequency of
rad s
−
1
, the average power dissipated in one cycle will be the same in both the circuits.
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Solution
For circuit (a)
P
a
=
V
2
r
m
s
R
For circuit (b)
P
b
=
v
2
r
m
s
Z
2
×
R
Given that,
P
a
=
P
b
⇒
V
2
r
m
s
R
=
v
2
r
m
s
Z
2
×
R
⇒
R
2
=
Z
2
⇒
25
=
(
√
(
X
C
−
X
L
)
2
+
5
2
)
2
⇒
25
=
(
X
C
−
X
L
)
2
+
25
⇒
X
C
=
X
L
⇒
1
ω
C
=
ω
L
⇒
ω
2
=
1
L
C
=
10
6
0.1
×
40
⇒
ω
=
500
rad s
−
1
Hence,
500
is the correct answer.
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20
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