Two friends Harry and Jayesh were discussing about two numbers. They found the two numbers to be such that one was twice the other. However, both had the same number of prime factors, while the larger one had 4 more factors than the smaller one. What are the numbers?

40, 80

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20, 40

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30, 60

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50, 100

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Solution

The correct option is C 30, 60
Go throught the options.
The answer is option (c).
Because the number of factors of 30 ( $2 \times 3 \times 5) = 8$
and the number of factors of $60 (2^{2} \times 3 \times 5) = 12$

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Two friends Harry and Jayesh were discussing about two numbers. They found the two numbers to be such that one was twice the other. However, both had the same number of prime factors, while the larger one had 4 more factors than the smaller one. What are the numbers?

The correct option is C 30, 60Go throught the options. The answer is option (c). Because the number of factors of 30 (2×3×5)=8 and the number of factors of 60(22×3×5)=12

The correct option is C 30, 60
Go throught the options.
The answer is option (c).
Because the number of factors of 30 ( $2 \times 3 \times 5) = 8$
and the number of factors of $60 (2^{2} \times 3 \times 5) = 12$