Two masses each of mass 0.10kg are moving with velocity 3m/s along x axis and 5m/s along y axis respectively. After an elastic collision, one of the masses moves with a velocity 4^i+4^j. The energy of the other mass after collision is
A
0J
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B
1J
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C
0.1J
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D
1.4J
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Solution
The correct option is C0.1J As we know,
For elastic collision, KEi=KEf
Assume speed after collision is v1 and v2.
Given, v1=√42+42=√32
KEi=KEf ⇒12×m×(5)2+12×m×(3)2=12×m×(√32)2+12×m×v22 ⇒34=32+v22 ⇒v22=2
Hence, K.E. of second mass after collision is KE=12m(v2)2=12×0.1×2=0.1J