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Question

Two particle execute S H M of same amplitude and frequency along the same straight line, They pass one another going in opposite direction each time their displacement is half of their amplitude. The phase difference between them is

A
0
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B
120
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C
180
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D
135
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Solution

The correct option is B 120
Accordingtoquestion.............Infirstcase:a2=asinωtsinωt=12andinsecondcase:a2=asin(ωt+φ)sin(ωt+φ)=12Now,sinωtcosφ+cosωtsinϕ=1212cosφ+114sinφ=123sinϕ=1cosφsin2φ=1+cos2φ2cosφ4cos2φ2cosφ2=0cosφ=134=12cosφ=12φ=1200sothatthecorrectoptionisB.

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