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Question

# Two particles execute S.H.M of same amplitude and frequency along the same straight line from same mean position. They cross one another without collision, when going in opposite direction, each time their displacement is half of their amplitude. The phase-difference between them is

A
0
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B
120
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C
180
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D
135
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Solution

## The correct option is B 120∘Since both particles have same amplitude and frequency, its equation isx1=xmcosωtx2=xmcos(ωt+ϕ)Crossing happens when x1=xm2So x1=xmcosωtxm2=xmcosωtωt=π3Similarly for x2, but it is moving in different direction so the closest value of ωt+ϕ=2π3ωt+ϕ=2π3π3+ϕ=2π3ϕ=π3Ans: 120 degreee

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