Two simple Harmonic Motions of angular frequency 100 and 1000 rad $S^{- 1}$ have the same displacement amplitude. The ratio of their maximum accelerations is :

10^{3}

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10^{4}

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1:10

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10^{2}

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Solution

The correct option is A 1: $10^{2}$
Maximum acceleration $a = - ω^{2} A$

$\frac{a_{1}}{a_{2}} = \frac{ω_{1}^{2} A}{ω_{2}^{2} A} = \frac{(100)^{2}}{(1000)^{2}} = \frac{1}{10^{2}}$

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Two simple Harmonic Motions of angular frequency 100 and 1000 rad S−1 have the same displacement amplitude. The ratio of their maximum accelerations is :

The correct option is A 1:102Maximum acceleration a=−ω2Aa1a2=ω21Aω22A=(100)2(1000)2=1102

Two simple Harmonic Motions of angular frequency 100 and 1000 rad $S^{- 1}$ have the same displacement amplitude. The ratio of their maximum accelerations is :

The correct option is A 1: $10^{2}$
Maximum acceleration $a = - ω^{2} A$

$\frac{a_{1}}{a_{2}} = \frac{ω_{1}^{2} A}{ω_{2}^{2} A} = \frac{(100)^{2}}{(1000)^{2}} = \frac{1}{10^{2}}$