Question

Under constant pressure, which fraction would be used to correct a given volume of gas at $300K$ to its new volume when it is heated to $333K$?

• A. $\frac{303-273}{60+273}$
• B. $\frac{60}{30}$
• C. $\frac{273}{333}$
• D. $\frac{303}{333}$
• E. $\frac{333}{303}$

Answer 1

The correct option is E $\frac{333}{303}$

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$
$V_1=$ initital volume
$V_2=$ final volume
$T_1=$ initial temperature $=300K$
$T_2=$ final temperature $=333K$
$\frac{V_1}{300}=\frac{V_2}{333}$
$V_2=\frac{333}{300}V1$
Hence, under constant pressure, the fraction $\frac{333}{303}$ would be used to correct a given volume of gas at $300K$ to its new volume when it is heated to $333K$.