Upon heating $K C l O_{3}$ in the presence of catalytic amount of $M n O_{2}$ , a gas W is formed. Excess amount of W reacts with white phosphorus to give X. The reaction of X with $H N O_{3}$ gives Y and Z.

W and X are, respectively

O_{3}

and

P_{4} O_{6}

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O_{2}

and

P_{4} O_{6}

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O_{2}

and

P_{4} O_{10}

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O_{3}

and

P_{4} O_{10}

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Solution

The correct option is C $O_{2}$ and $P_{4} O_{10}$
$2 K C l O_{3} M n O_{2} - --- \to 2 K C l + 3 O_{2} W$

$P_{4} + 5 O_{2} \to P_{4} O_{10}$
x

$P_{4} O_{10} + 4 H N O_{3} \to 4 H P O_{3} + 2 N_{2} O_{5}$

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Similar questions

Q. Upon heating

K C l O_{3}

in the presence of catalytic amount of

M n O_{2}

, a gas W is formed. Excess amount of W reacts with white phosphorus to give X. The reaction of X with

H N O_{3}

gives Y and Z.

Y and Z are, respectively

The reactions of $C l_{2}$ gas with cold-dilute and hot-concentrated NaOH in water give sodium salts of two different oxoacids of chlorine, P and Q, respectively. The $C l_{2}$ gas reacts with $S O_{2}$ gas, in presence of charcoal, to give a product R reacts with white phosphorus to give a compound S. On hydrolysis, S gives an oxoacid of phosphorus.

3. P and Q, respectively, are the sodium salts of

Q. Fusion of

M n O_{2}

with

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in presence of

O_{2}

produces a salt W. An alkaline solution of W upon electrolytic oxidation yields another salt X. The manganese containing ions present in W and X, respectively, are Y and Z. Correct statement(s) is(are)

Q. A gas (X) is obtained when copper reacts with dilute HN03. The gas thus formed reacts with oxygen to give brown fumes of (Y). (Y) when dissolved in water gives an important acid (Z) and the gas (X). X, Y, and Z respectively are:

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Upon heating KClO3 in the presence of catalytic amount of MnO2, a gas W is formed. Excess amount of W reacts with white phosphorus to give X. The reaction of X with HNO3 gives Y and Z. W and X are, respectively

The correct option is C O2 and P4O102KClO3MnO2−−−−→2KCl+3O2W P4+5O2→P4O10 x P4O10+4HNO3→4HPO3+2N2O5

Upon heating $K C l O_{3}$ in the presence of catalytic amount of $M n O_{2}$ , a gas W is formed. Excess amount of W reacts with white phosphorus to give X. The reaction of X with $H N O_{3}$ gives Y and Z.

W and X are, respectively

The correct option is C $O_{2}$ and $P_{4} O_{10}$
$2 K C l O_{3} M n O_{2} - --- \to 2 K C l + 3 O_{2} W$

$P_{4} + 5 O_{2} \to P_{4} O_{10}$
x

$P_{4} O_{10} + 4 H N O_{3} \to 4 H P O_{3} + 2 N_{2} O_{5}$