Question

What is the probability that a leap year selected at random will contain 53 Sundays?

• A. $\frac{1}{2}$
• B. $\frac{2}{7}$
• C. $\frac{5}{7}$
• D. $\frac{6}{7}$

Answer 1

The correct option is B $\frac{2}{7}$

In a leap year there are 366 days.
366 days = 52 weeks and 2 days.
These remaining two days can be
(a) Sunday, Monday
(b) Monday, Tuesday
(c) Tuesday, Wednesday
(d) Wednesday, Thursday
(e) Thursday, Friday
(f) Friday, Saturday
(g) Saturday, Sunday
$\therefore$ Total no. of cases (a to g) = 7
No. of favourable cases (a, g) = 2
$\therefore$ Required probability $=\frac{2}{7}$