Which one is the correct order of acidity?

C H \equiv C H > C H_{2} = C H_{2} > C H_{3} - C \equiv C H > C H_{3} - C H_{3}

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C H_{3} - C H_{3} > C H_{2} = C H_{2} > C H_{3} - C \equiv C H > C H \equiv C H

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C H_{2} = C H_{2} > C H_{3} - C H = C H_{2} > C H_{3} - C \equiv C H > C H \equiv C H

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C H \equiv C H > C H_{3} - C \equiv C H > C H_{2} = C H_{2} > C H_{3} - C H_{3}

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Solution

The correct option is D $C H \equiv C H > C H_{3} - C \equiv C H > C H_{2} = C H_{2} > C H_{3} - C H_{3}$
As the s-character of carbon atom increases its acidic strength increases,The correct of s-character of carbon atom increases in the order $s p > s p^{2} > s p^{3}$ . Hence the correct order of acidity is $s p C H \equiv C H > C H_{3} - s p C \equiv C H > s p^{2} C H_{2} = C H_{2} > s p^{3} C H_{3} - C H_{3}$

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