A car starts from rest and moves along the x-axis with constant acceleration of 5 m/s2 for 8 seconds. If it then continues with constant velocity, what distance will the car cover in 12 seconds since it started from the rest?

Answer:

Car Starts from rest hence

  • Initial velocity (u) = 0
  • Acceleration (a) = 5 m/s2
  • Time (t) = 8s

v = u + at

v = 0 + (5 × 8)

From second equation

s1 = ut +12at2

s1 = (0 x 8) + 1/2x 5 x (8)2

s1 = 1/2 x 5 x (8)2

s1 = 1/2 x 5 x 64

s1 = 5 × 32

s1 = 160

The velocity attained in 8 seconds is given by
v = u + at
v = 0 + (5 × 8)
v = 40m/s
The distance travelled in the next 4 seconds is
s2= 40 × 4
s2= 160m
So, the total distance travelled by car is
s1 + s2 =160 + 160 = 320m

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