sinhπ6i=
-i2
i2
i32
-i32
Simplifying the given expression using trigonometric identities:
sinhπ6i=i×sinπ6∵sinh(xi)=isinx=i×12=i2
Thus, sinhπ6i=i2
Therefore, option (B) is the correct answer.
Evaluate :cos48°-sin42°