wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

The maximum value of z=9x+13y, subject to constraints 2x+3y18, 2x+y10, x0 and y0 is


A

130

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

81

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

79

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

99

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C

79


Explanation for the correct option:

Step 1: Find the critical points of the given function.

In the question, a function z=9x+13y is given, and the constraints 2x+3y18, 2x+y10, x0, and y0 is also given.

Draw a graph describing the given inequalities as follows:

From the graph, it is clear that the critical points are (0,6),(0,0),(5,0) and (3,4).

Step 2: Find the maximum value of the given function.

Since, the critical points are (0,6),(0,0),(5,0) and (3,4).

Evaluate z for (0,6) as follows:

z=9(0)+13(6)z=78

So, the value of z for (0,6) is 78.

Similarly, Evaluate z for (0,0) as follows:

z=9(0)+13(0)z=0

So, the value of z for (0,0) is 0.

Similarly, Evaluate z for (5,0) as follows:

z=9(5)+13(0)z=45

So, the value of z for (5,0) is 45.

Similarly, Evaluate z for (3,4) as follows:

z=9(3)+13(4)z=79

So, the value of z for (3,4) is 79.

Therefore, the maximum value of the given function is 79.

Hence, option C is the correct answer.


flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Properties of Inequalities
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon