The value of tanh-12-1 is
log2
log2-1
log3
None of these.
Explanation for the correct option
The given trigonometric expression: tanh-12-1.
It is known that tanh-1(x)=log[1+x1-x]2.
Thus, tanh-12-1=log1+2-11-2-12.
⇒tanh-12-1=log1+121-122⇒tanh-12-1=log32122⇒tanh-12-1=log32⇒tanh-12-1=log312⇒tanh-12-1=log3
Hence, option C is correct .
Q14. If α,β are the zeros of polynomial fx=x2-px+1-c then α+1β+1 is equal to: