Question

What is the differential form of Gauss law?

Answer 1

1. According to the Gauss law at any point in the space, the divergence of the electrical field $\nabla .\left(E\right)$ is equal to the $\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{${\epsilon }_0$}\right.$times the volume of the charge density $\left(\rho \right)$ of that point. ${\epsilon }_0(epsilon-nought)=permittivityoffreespace$
2. In expression it can be written as: $\nabla .E=\frac{\rho }{{\epsilon }_0}$.