0.5g of an organic compound on Kjeldahl’s analysis gave enough ammonia to just neutralise 10 $c m^{3}$ of 1M $H_{2} S O_{4}$ . The $%$ of N in the compound is:

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Solution

The correct option is A. 56
According Kjeldahl’s analysis the % of nitrogen formula is
$% o f N = \frac{1.4 \times M o l a r i t y \times V o l u m e \times B a s i c i t y o f a c i d}{M a s s o f s u b s t a n c e t a k e n}$
$% o f N = \frac{1.4 \times 1 \times 10 \times 2}{0.5} = 56$
The percentage of nitrogen is 56%

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0.5g of an organic compound on Kjeldahl’s analysis gave enough ammonia to just neutralise 10 cm3 of 1M H2SO4. The % of N in the compound is:

The correct option is A. 56According Kjeldahl’s analysis the % of nitrogen formula is%ofN=1.4×Molarity×Volume×BasicityofacidMassofsubstancetaken%ofN=1.4×1×10×20.5=56The percentage of nitrogen is 56%

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