Question

$\left(1^0+2^0+3^0\right)$ is equal to

• A. $0$
• B. $1$
• C. $3$
• D. $6$

Answer 1

The correct option is C

$3$

From the law of exponents , we know that $a^0=1.$

Hence , $1^0=1$

$2^0=1$

$3^0=1$

Then , $$\begin{gathered} \left(1^0+2^0+3^0\right)=\left(1+1+1\right) \\ =3 \end{gathered}$$

Hence, Option C is the correct answer.