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Standard XII

Chemistry

Enthalpy of Solution

1*10^-3 m sol...

Question

1*10^-3 m solution of Pt(NH3)4Cl4 in water shows depression in freezing point by 0.0054 C. The given structure of the following compound will be (Given Kf=1.85 K/m) (1) [Pt(NH3)4]Cl4 (2) [Pt(NH3)3Cl]Cl3 (3) [Pt(NH3)Cl2]Cl2 (4) [Pt(NH3)Cl3]Cl.

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A 0.001 molal solution of in water had a freezing point depression of 0.0054°C. If K_f for water is 1.80, the correct formulation for the above molecule is

Q. A 0.001 molal solution of

[P t (N H_{3})_{4} c l_{4}]

in water had a freezing point depression of

{0.0054}^{\circ}

. If

K_{f}

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0.001

molal solution of

[P t {({N H}_{3})}_{4} {C l}_{4}]

in water had a freezing point depression of

0.0054^{o} C

. If

K_{f}

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, the correct formula of the compound is :

Q. A 0.001 molal solution of

[P t (N H_{3})_{4} C l_{4}]

in water has a freezing point depression of

{0.0054}^{0} C

. If

K_{f}

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^{- 1}

, the correct formulation of the above molecule is:

The freezing point depression of

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molal aqueous solution of a compound

K_{x} [F e (C N)_{6}]

7.44 \times 10^{- 3}

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