1.2+2.22+3.23+.................+n.2n=(n−1)2n+1+2 is true for
A
Only natural number n≥3
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B
All natural number n
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C
Only natural number n≥5
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D
None
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Solution
The correct option is B All natural number n Let P(n) be the given statement i.e. P(n):1.2+2.22+3.23+.........+n.2n=(n−1)2n+1+2 Putting n = 1, LHS = 1.2 = 2; RHS = 0+2 = 2 ∴ P(n) is true for n=1 Assume that P(n) is true for n=k i.e. P(k) is true i.e. 1.22+2.22+3.23+...........+k.2k Replacing k by k + 1, we get the next term =(k+1)2k+1 Adding it to both sides LHS=1.2+2.22+3.23+.........+k.2k+(k+1)2k+1 RHS=(k−1)2k+1+2+(k+1)2k+1
=2k+1[k−1+k+1]+2=2k2k+1+2=(k+1−1)2k+1+1+2
This proves P(n) true for n=k+1 Thus P(k+1) is true whenever P(k) is true Hence. P(n) is true for all n ∈ N