19of65is ………..
We have,
19of65=19×65=645=6÷345÷3(dividingbothNrandDrby3)=215
Therefore, 215 is the required solution
The sum of the series 23!+45!+67!+... to ∞ = ae. Find (a+3)2.
loge(n+1)−loge(n−1)=4a[(1n)+(13n3)+(15n5)+...∞] Find 8a.