Sum of the First n Odd Natural Numbers Is Equal to n Squared
1+a+b+a b
Question
1+a+b+ab
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Solution
1 + a +b+ ab group them in pairs (1+a) + (ab+ b) take b common from second bracket =(1+a)+b(1+ a) now your brackets are the same so you can group them (1+b)(1+a) which is the final answer