1 A∘ is equal to :
(a) 0.1 nm (b) 10−10 cm
(c) 10−8 m (d) 104 μ
1 A∘ = 10−10 m = 0.1 ×10−9 m = 0.1 nm
Hence, the correct choice is (a)
An electron has kinetic energy 2.8×10−23J de-Broglie wavelength will be nearly (m_e = 9.1 \times 10^{-31} kg\)