Question

1 g of ice at $0^{o}C$ is supplied with 500 J of heat energy. Explain the temperature change of material.

Answer 1

as the ice is already at 0 C there wont be any temperature change but only phase change hence the energy required for this change is

$Q=m\Delta H_f$

where m is the mass and $H_f$ is the heat of fusion

$Q_1=1g\times 334J/g=334J$

Now heat required to change the temperature of water to 100 C is

$Q=mc\Delta T$

$Q_2=1g\times 4.18\times (100-0)=418J$

As we dont have sufficient energy to boil water to 100 C therefore water must be boiling at low temp and hence there wont be any state change

the energy left after first state change is

$Q_2=500-Q_1=166J$

$Q_2=mc\Delta T$

$166=1\times 4.186\times (T-0)$

$T={39.66}^{o}C$