$1 k g f$ $c m$ $^{- 2}$ .................. Nm $^{- 2}$ .

10^{3}

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10^{5}

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10^{4}

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10^{6}

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Solution

The correct option is D $10^{5}$
$1 k g f$ is the amount of gravitational force acting on $1 k g$ of a body.
$1 k g f = 10 N$

And $1 m = 100 c m$ ,
so $1 k g f / c m^{2} = 10 \times 10^{4} N / m^{2}$

we will get $10^{5} N / m^{2}$

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Similar questions

Tick the correct answer:- In a homogeneous solution, the dimension of solute particles varies between:
a. 1 – 103 nm b. 104 - 106 nm
c. 105 - 106 nm d. 108 – 109 nm

Write the numeral whose expanded form is given below:
(i) $6 \times 10^{4} + 3 \times 10^{3} + 0 \times 10^{2} + 7 \times 10^{1} + 8 \times 10^{0}$
(ii) $9 \times 10^{6} + 7 \times 10^{5} + 0 \times 10^{4} + 3 \times 10^{3} + 4 \times 10^{2} + 6 \times 10^{1} + 2 \times 10^{0}$
(iii) $8 \times 10^{5} + 6 \times 10^{4} + 4 \times 10^{3} + 2 \times 10^{2} + 9 \times 10^{1} + 6 \times 10^{0}$

Q. Write the number :

4 \times 10^{6} + 8 \times 10^{5} + 6 \times 10^{4} + 4 \times 10^{3} + 4 \times 10^{2} + 6 \times 10 + 9 \times 10^{0}

Question 63

$4 \times 10^{5} + 3 \times 10^{4} + 2 \times 10^{3} + 1 \times 10^{0} = 432010$

Express the following standard form.

(a) 5 × 10⁶ + 4 × 10⁵ + 2 × 10³ + 9 × 10² + 6 × 10⁰

(b) 4 × 10⁵ + 8 ×10³ + 7 × 10¹

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1kgf cm −2 .................. Nm−2 .

The correct option is D 1051kgf is the amount of gravitational force acting on 1kg of a body.1 kgf = 10 NAnd 1m=100cm , so 1kgf/cm2=10×104 N/m2we will get 105 N/m2

$1 k g f$ $c m$ $^{- 2}$ .................. Nm $^{- 2}$ .

The correct option is D $10^{5}$
$1 k g f$ is the amount of gravitational force acting on $1 k g$ of a body.
$1 k g f = 10 N$

And $1 m = 100 c m$ ,
so $1 k g f / c m^{2} = 10 \times 10^{4} N / m^{2}$

we will get $10^{5} N / m^{2}$