10 mL of 0.2 N HCl and 30 mL of 0.1 N HCl together exactly neutralises 40 mL of solution of NaOH which is also exactly neutralised by a solution in water of 0.61 g of an organic acid. What is the equivalent weight of the organic acid?
A
61
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B
91.5
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C
122
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D
183
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Solution
The correct option is C 122 1geqHCl≡1geqNaOH≡geqacid The number of g eq of HCl =10mL1000mL/L×0.2N+30mL1000mL/L×0.1N=0.005eq This corresponds to 0.005 g eq of acid. The equivalent weight of the acid is 0.61g0.005geq=122.