12 gms of gas occupies a volume of 4×10−3m3 at a temperature of 7∘C. After the gas is heated at constant pressure its density becomes 6×10−4gm/cc. The temperature to which the gas was heated is:
A
1000 K
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B
1400 K
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C
1200 K
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D
800 K
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Solution
The correct option is B 1400 K PV=nRT=wMRT Hence, P=ρMRT Initially, PV=wMRT1 ......(1) After heating, P=ρMRT2 ......(2) From equations (1) and (2), The temperature to which the gas was heated is T2=wT1ρV=12×2806×10−4×4×103=1400