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Standard VIII
Chemistry
Collision Theory
13. If activa...
Question
13. If activation energy of a backward reaction is -20 kJ/mol and that of forward reaction is 40kJ/mol, then enthalpy change for the reaction is 1. 20kJ/mol 2. 60kJ/mol 3. -20kJ/mol 4. -60kJ/mol Kindly explain with graph
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Similar questions
Q.
The activation energy for the forward reaction
X
→
Y
is
60
K
J
m
o
l
−
1
and
Δ
H
is
−
20
K
J
m
o
l
−
1
. The activation energy for the backward reaction
Y
→
X
is:
Q.
The activation energy for the forward reaction
X
→
Y
is
60
k
J
m
o
l
−
1
and
Δ
H
is
−
20
k
J
m
o
l
−
1
. The activation energy for the reverse reaction is:
Q.
For a given reaction, energy of activation for forward reaction
(
E
a
f
)
is
80
k
J
/
m
o
l
.
Δ
H
=
−
40
k
J
/
m
o
l
for the reaction. A catalyst lowers
E
a
f
to
20
k
J
/
m
o
l
. The ratio of energy of activation for reverse reaction before and after addition of catalyst is:
Q.
The forward and backward activation energy of exothermic reaction
A
→
B
is
80
and
280
k
J
m
o
l
−
1
respectively. The enthalpy change of the forward reaction
A
→
B
( in
k
J
/
m
o
l
) will be :
Q.
In a reversible reaction, the enthalpy change and the activation energy in the forward direction are respectively
−
x
k
J
m
o
l
−
1
and
y
k
J
m
o
l
−
1
. Therefore, the energy of activation in the backward direction, in
k
J
m
o
l
−
1
is:
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