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Question

15. cot 4x (sin 5x +sin 3x) cot x (sin 5x - sin 3x)

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Solution

The given trigonometric equation is,

cot4x( sin5x+sin3x )=cotx( sin5xsin3x )

Solve left hand side,

L.H.S.=cot4x( sin5x+sin3x ) =cot4x×2sin ( 5x+3x ) 2 cos ( 5x3x ) 2 =cot4x×2sin 8x 2 cos 2x 2 = cos4x sin4x ×2sin4xcosx

Further simplify,

L.H.S.=2cos4xcosx =2cos4xsinx× cosx sinx =[ { sin( 4x+x )sin( 4xx ) } ]×cotx =cotx( sin5xsin3x )

Right hand side is,

R.H.S.=cotx( sin5xsin3x )

Hence, L.H.S.=R.H.S.


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