18.solve (3/2log2 + 3/2log3 + 3/2log5)÷ (log2 + log3 - log5)

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2 {log}_{3} x + {log}_{3} (x^{2} - 3) = {log}_{3} 0.5 + 5^{{log}_{5} ({log}_{3} 8)}

Log6+ 2log5+log4-log3-log2=2

Prove it

x

log 2 + log (x + 3) - log (3 x - 5) = log 3

α, β

x^{2} - ({3 + 2}^{\sqrt{{log}_{2} 3}} - 3^{\sqrt{{log}_{3} 2}}) x - 2 (3^{{log}_{3} 2} - 2^{{log}_{2} 3}) = 0

α, β

{log}_{2} [{log}_{3} ({log}_{2} x)] = 1

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