The correct option is B False We know that a^m × b^m = (a × b)^m Using this law, we get a = 2, b = 4 ⇒ a × b = 8 (2)^5 ×(4)^5 = (8)^5 Hence, the given state ...

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Byju's Answer

Standard VII

Mathematics

Dividing a Polynomial by a Polynomial

25×45=245 .

Question

${(2)}^{5} \times {(4)}^{5} = {(24)}^{5}$ .

True

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False

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Solution

The correct option is B
False

We know that $a^{m} \times b^{m} = {(a \times b)}^{m}$

Using this law, we get

$a = 2, b = 4 \Rightarrow a \times b = 8$

${(2)}^{5} \times {(4)}^{5} = {(8)}^{5}$

Hence, the given statement is false.

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Similar questions

Q. State whether true or false

{(2)}^{5} \times {(4)}^{5} = {(24)}^{5}

{cos}^{2} 45 - tan 45 = sin θ

find

sin θ

Evaluate:

${cos}^{2} 25^{\circ} - {sin}^{2} 65^{\circ} - {tan}^{2} 45^{\circ}$

Q. Given

\sqrt{5} = 2.236

the value of

\sqrt{45} + \sqrt{605} - \sqrt{245}

correct to

3

decimal places is

What must be subtracted from 3 $\sqrt[2]{45}$ + 2 $\sqrt[2]{75}$ + $\sqrt[2]{245}$ to get $\sqrt[2]{5}$

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(2)5×(4)5=(24)5.

The correct option is B False We know that am×bm=(a×b)m Using this law, we get a=2,b=4⇒a×b=8 (2)5×(4)5=(8)5 Hence, the given statement is false.

${(2)}^{5} \times {(4)}^{5} = {(24)}^{5}$ .

The correct option is B
False

We know that $a^{m} \times b^{m} = {(a \times b)}^{m}$

Using this law, we get

$a = 2, b = 4 \Rightarrow a \times b = 8$

${(2)}^{5} \times {(4)}^{5} = {(8)}^{5}$

Hence, the given statement is false.