2sin45°cos45°=1, how?
Show that2sin45°cos45°=1
2sin45°cos45°=1
LHS=2sin45°cos45°=2×12×12∵sin45°=cos45°=12=2×12=1.....1RHS=1.......2
from1 and2,
∴2sin45°cos45°=1
Hence proved.
How is n!(n+1)= (n+1)!
how( 1-underoot 2 / -1 = underoot 2 -1 )
$ how ( 2 underoot 5- 5 underoot 2 / -30 = 5 underoot 2 - 2 underoot 5 / 30 )