Question

20 kg + 500 g + 200 mg + 11.5 kg = ___ g

• A. 32000.2 g
• B. 28000 g
• C. 30000 g
• D. 31000.4 g

Answer 1

The correct option is A 32000.2 g

1 kg = 1000 g
20 kg = 20 × 1000 g = 20000 g
11.5 kg = 11.5 × 1000 g = 11500 g

Now, 1 g = 1000 mg
$\Rightarrow$ 1 mg = $\frac{1}{1000}$ g
$\Rightarrow$ 200 mg = 200 × $\frac{1}{1000}$ g
= 0.2 g

$$\begin{array}{cc}\text{grams}& \\ 20000.000& \\ 500.000& \\ 0.200& \\ \underset{–}{+11500.000}& \\ 32000.200& \end{array}$$

$\therefore$ The missing value is 32000.2 g.