Question

$24u^2{v}^{3}w\times 8vw=$

• A. $192u^2{v}^4{w}^2$
• B. $192u^0{v}^4{w}^2$
• C. $32u^2{v}^4{w}^2$

Answer 1

The correct option is A $192u^2{v}^4{w}^2$

We know anything power zero is 1.
$\Rightarrow$ $1=u^0$
Using the above fact the 2nd term can be written as
$8vw=8\times 1\times v\times w=8\times u^0\times v\times w$
Applying commutative rule for multiplication and adding the exponents of the respective unknowns of both terms we get,
$24u^2{v}^{3}w\times 8u^{0}vw$
= $(24\times 8)\times (u^2{v}^{3}w\times u^{0}vw)$
= $192\times u^{(2+0)}\times v^{(3+1)}\times w^{(1+1)}$
= $192u^2{v}^4{w}^2$