250 J work is done to lift a bucket of mass 10 kg at a certain height. Calculate the height through which the bucket is lifted. Consider acceleration due to gravity as 10 $\frac{m}{s^{2}}$ .

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Solution

Given:
Mass of the bucket = 10 kg
Work done on the bucket = 250 J
Calculation:
We know that the work done on lifting a mass m through a height h = mgh
$H e i g h t t h r o u g h w h i c h t h e b u c k e t i s l i f t e d (h) = \frac{w o r k d o n e t o l i f t t h e b u c k e t}{m a s s o f t h e b u c k e t \times g} H e i g h t t h r o u g h w h i c h t h e b u c k e t i s l i f t e d (h) = \frac{250 J}{10 k g \times 10 \frac{m}{s^{2}}} H e i g h t t h r o u g h w h i c h t h e b u c k e t i s l i f t e d (h) = 2.5 m$
Hence, the height through which the bucket is lifted (h) is 2.5 m.

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250 J work is done to lift a bucket of mass 10 kg at a certain height. Calculate the height through which the bucket is lifted. Consider acceleration due to gravity as 10 ms2.

250 J work is done to lift a bucket of mass 10 kg at a certain height. Calculate the height through which the bucket is lifted. Consider acceleration due to gravity as 10 $\frac{m}{s^{2}}$ .