If a +b +c =5 and ab +bc+ca =10,then prove that a cube +b cube+c cube -3abc =-25
If the roots of the equation (csq-ab) xsq-2(asq-bc)x+bsq-ac=0 are equal prove that a=0 /a cube +b cube+c cube=3abc
a+b+c=15 and a square + b square + c square =83
Find the value of a cube + b cube + c cubeb - 3abc