√2x + √3y =0 ------- (1)
√3x - √8y =0 ------- (2)
Multiply eqn 1 with √8
We get,
4x +2√6y =0 ------(3)
Multiply eqn 2 with √3
We get,
3x - 2√6y =0 ------(4)
Add eqn (3) & (4)
We get,
4x+2√6y=0 +
3x -2√6y=0
--------------------
7x =0
Therefore x=0
Substituting x in any above eqn we will get y=0