√2x+√3y=0,√3x-√8y=0 solve by elimination method

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Solution

√2x + √3y =0 ------- (1)
√3x - √8y =0 ------- (2)

Multiply eqn 1 with √8
We get,
4x +2√6y =0 ------(3)

Multiply eqn 2 with √3
We get,
3x - 2√6y =0 ------(4)

Add eqn (3) & (4)
We get,
4x+2√6y=0 +
3x -2√6y=0
--------------------
7x =0

Therefore x=0
Substituting x in any above eqn we will get y=0

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Solve the pair of linear equations by substituting method:-

√2x+√3y=0

√3x-√8y=0

\sqrt{2} x + \sqrt{3} y = 0, \sqrt{3} x - \sqrt{8} y = 2

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3 x + 4 y = - 25

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