We have, #10; #10; ( 2x+3y )^2 16z^2 #10; #10; ⇒( 2x+3y )^2 ( 4z #10;)^2 ( ∴A^2 B^2=( A+B )( #10;A B ) ) #10; #10; ⇒( 2x+3y+4z ) ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Division of a Polynomial by a Polynomial

2x+3y 2 -16 z...

Question

$(2 x + 3 y)^{2} - 16 z^{2}$

Open in App

Solution

We have,

${(2 x + 3 y)}^{2} - 16 z^{2}$

$\Rightarrow {(2 x + 3 y)}^{2} - {(4 z)}^{2} (∴ A^{2} - B^{2} = (A + B) (A - B))$

$\Rightarrow (2 x + 3 y + 4 z) (2 x + 3 y - 4 z)$

Hence, this is the answer.

Suggest Corrections

Similar questions

2 x^{2} + 3 y^{2} + 4 z^{2} - \sqrt{6} x y - 2 \sqrt{3} y z - 2 \sqrt{2} x z = 0

(2 x^{2} + 3 y^{2} + 16 z^{2} + 2 \sqrt{6} x y - 8 \sqrt{3} y z - 8 \sqrt{2} x z)

(2 x + y + 4 z) (4 x^{2} + y^{2} + 16 z^{2} - 2 x y - 4 y z - 8 z x)

(2 x + \frac{1}{3 y})^{2} - (2 x - \frac{1}{3 y})^{2}

\frac{2 x}{3 y} = \frac{3 y}{4 z}

4 x^{2} + 9 y^{2} + 16 z^{2} = (2 x - 3 y + 4 z) (2 x + 3 y + 4 z)

(2 x + 3 y)^{2}

(2 x - 3 y)^{2}

(2 x + 3 y) (2 x - 3 y)

Join BYJU'S Learning Program