(2x−3y)3+(x+3y)3+3(2x−3y)2(x+3y)+3(2x−3y)(x+3y)2=
Substitute 2x−3y=a and (x+3y)=b ⇒(2x−3y)3+(x+3y)3+3(2x−3y)2(x+3y)+3(2x−3y)(x+3y)2 =a3+b3+3a2b+3ab2 =(a+b)3 =(2x−3y+x+3y)3 =(3x)3 =27x3