2x4 - 3x3 - 4x - 2x2- x - 3-

Divide (2x^4+3x^3+4x 2x^2) by (x+3) #160; #160; #160; #160; #160; #160; #160; #160; #160; #160; 2x^3 3x^2+7x 17 # ...

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Long Division Method to Divide Two Polynomials

2x4 + 3x3 + 4...

Question

$(2 x^{4} + 3 x^{3} + 4 x - 2 x^{2}) \div (x + 3)$ .

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Solution

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(2 x^{4} + 3 x^{3} + 4 x - 2 x^{2}) \div (x + 3)

[(4 x^{4} - 3 x^{3} - 2 x^{2} + 4 x - 3)

(x - 1)

({2 x}^{4} + {3 x}^{3} + 4 x - 2) \div (x + 2)

By actual division , shows that $x^{2} - 3$ is a factor of $2 x^{4} + 3 x^{3} - 2 x^{2} - 9 x - 12.$

p(x)= 2x⁴ - 3x³ + 2x² + 2x - 1 is divided by (x - 2) and q(x) = 3x³ - 2x² + x - 1 is divided by (x - 1). So, twice the sum of the remainders is:

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