Question

$2x\times \frac{3}{x}=$

Answer 1

$\frac{1}{x}$ can be written as $x^{-1}$.
$\therefore$ The expression becomes $2x\times 3x^{-1}$
Applying commutative property, we ger,
$2x\times 3x^{-1}=(2\times 3)\times (x\times x^{-1})$
$\Rightarrow$ $2x\times 3x^{-1}=6\times (x\times x^{-1})$
Adding exponents, we get,
$6\times (x\times x^{-1})=6\times x^{(1+(-1\left)\right)}=6x^0$
We know anything power zero is always 1.
$\therefore$ $2x\times \frac{3}{x}=6x^0=6\times 1=6$