Question

2xcube -xy square -ycube........factorize

Answer 1

Let P(x) = 2 x³ - x y² - y³
We see that if x = y, then P(x=y) = 0. Then by Remainder and factor theorem, (x - y) is a factor.

let P(x) = (x - y) [ 2 x² - a x y + y² ]
= 2 x³ - a x² y + x y² - 2 x² y + a x y² - y³
= 2 x³ - (a+2) x² y + (a+1) x y² - y³

By comparing coefficients: a = -2

P(x) = ( x - y) [2 x² + 2 x y + y² ]


Read more on Brainly.in - https://brainly.in/question/762523#readmore