3 (3x-1/2x+3)-2 (2x+3/3x-1)=5

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3 [\frac{3 x - 1}{2 x + 3}] - 2 [\frac{2 x + 3}{3 x - 1}] = 5; x \neq \frac{1}{3}, - \frac{3}{2}

$\frac{(2 x - 1)}{3} \geq \frac{(3 x - 2)}{3} \geq \frac{(3 x - 2)}{4} - \frac{(2 - x)}{5}$

Solve the equations:

(i) 5x = 3x + 24;

(ii) 8t + 5 = 2t − 31;

(iii) 7x − 10 = 4x + 11;

(iv) 4z + 3 = 6 + 2z;

(v) 2x − 1 = 14 − x;

(vi) 6x + 1 = 3(x − 1) + 7;

(vii) ;

(viii) ;

(ix) 3(x + 1) = 12 + 4 (x − 1);

(x) 2x − 5 = 3(x − 5);

(xi) 6(1 − 4x) + 7(2 + 5x) = 53;

(xii) 3(x + 6) + 2 (x + 3) = 64;

(xiii) ;

(xiv) .

\frac{2 x - 3}{2 x - 1} = \frac{3 x - 1}{3 x + 5}

\frac{2 x - 3}{2 x - 1} = \frac{3 x - 1}{3 x + 5}

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