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Question

3. хгех

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Solution

The given integral is given below as,

I= x 2 e x dx

Use integration by parts rule. Consider x 2 as first function and e x as second function.

I= x 2 e x dx = x 2 e x dx ( d dx x 2 e x dx ) dx = x 2 e x 2 x e x dx

Again by using integration by parts, we get

I= x 2 e x 2[ x e x dx ( d dx x e x dx )dx ] = x 2 e x 2[ x e x e x dx ] = x 2 e x 2x e x +2 e x +C I=( x 2 2x+2 ) e x +C

Thus, the integration of x 2 e x dx is ( x 2 2x+2 ) e x +C.


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