Simplify: 3(n-4)+2(4n-5)=5(n+2)+16
We have, 3(n-4)+2(4n-5)=5(n+2)+16
By distributive property, we know x.(y+z)=x.y+x.z. Hence, applying the same in the given equation we get;
3n−12+8n−10=5n+10+1611n−22=5n+26
Moving the variable terms on one side of the equation, we get;
11n−5n=22+266n=48n=486n=8
Hence, the value of nis 8.
Simplify the following:3n×9n+13n−1×9n−1