30. Prove that , sin20.sin40.sin60.sin80 = 3/16 . Thanks.

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sin 20^{\circ} sin 40^{\circ} sin 60^{\circ} sin 80^{\circ} = \frac{3}{16}

sin 20

sin 40

sin 60

sin 80 = \frac{3}{16}

{s i n 20}^{\circ} s i n 40^{\circ} {s i n 80}^{\circ} = \frac{\sqrt{3}}{8}

$s i n 20^{\circ} s i n 40^{\circ} s i n 60^{\circ} s i n 80^{\circ}$ =

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